New York to Comayagua
Distance3,213 km1,997 miles · 1,735 nautical miles
- Flight time
- about 4 h 30 min direct, estimated
- Heading
- south-west 209° at departure
- From
- John F. Kennedy International Airport United States
- To
- Palmerola International Airport Honduras
- Type
- International · medium-haul
Questions
How far is New York from Comayagua by plane?
The great-circle distance between John F. Kennedy International Airport and Palmerola International Airport is 3,213 km (1,997 miles). Real flight paths are usually a little longer because of airways, weather and air traffic control.
How long is the flight from New York to Comayagua?
About 4 h 30 min for a direct flight, estimated at 800 km/h plus 30 minutes for take-off and landing. Scheduled times vary with the airline, the aircraft and the winds, and the return can differ by an hour or more on long flights.
Which direction do you fly?
Planes leave New York heading south-west (209°) on the shortest path.
Routes from New York
- New York to Toronto588 km
- New York to Chicago1,188 km
- New York to Atlanta1,222 km
- New York to Mexico City3,365 km
- New York to Los Angeles3,974 km
- New York to London5,540 km
Routes to Comayagua
- Mexico City to Comayagua1,341 km
- Atlanta to Comayagua2,165 km
- Chicago to Comayagua3,069 km
- Toronto to Comayagua3,345 km
- Los Angeles to Comayagua3,781 km
- Sao Paulo to Comayagua6,140 km
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